Anyone able to solve this in less than 50 secs?

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The only way this works is if the result is a perfect square, and the roots of that perfect square are primes.

So it's (perfect square) x 1, and the perfect square is less than 100.

The options for it are 4, 9, 25, 49, (121 would be next but it's over 100).

Note that you can pick each of them two ways (e.g., 4 first then 1 vs. 1 first then 4). So 8 options.

Denominator is just 100x99.

Simplify and get 2/(25x99)

Edit: and yes this should take under a minute. The moment you see that the number of factors is odd you should think perfect square.

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If a and b are distinct, won't a*b always
have at least FOUR factors? 1, a, b, and ab only happens if a and b are primes.

If they are not counting 1 and the number itself as factors, then the only numbers that would produce only 3 factors are prime #s ^ 4, where prime #^3 is less than or equal to 100

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